Cost of painting walls of room $8\times6\times3$ at ₹$5$/m² =
Cost of painting walls of room $8\times6\times3$ at ₹$5$/m² =
- ₹$420$
- ₹$240$
- ₹$540$
- ₹$720$
Solution
LSA $=2\cdot3(8+6)=84$; cost $=84\cdot5=420$.
Asked in: MH-SSC-9
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