Copper has face centered cubic (fcc) lattice with interatomic spacing equal to $2.54 Å$. The value of…

Copper has face centered cubic (fcc) lattice with interatomic spacing equal to $2.54 Å$. The value of lattice constant for this lattice is:
  1. $2.54 Å$
  2. $3.59 Å$
  3. $1.27 Å$
  4. $5.08 Å$

Solution

Given $2 \pi=2.54 Å$ $\Rightarrow \quad r=\frac{2.54}{2}=1.27 Å$ For fcc lattice: $\begin{aligned} r & =\frac{a}{2 \sqrt{2}} \\ a & =r 2 \sqrt{2} \\ & =1.27 \times 2 \times 1.44 \\ & =3.59 \mathrm{~A}^{\circ} \end{aligned}$

Asked in: NEET 2005

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