Coordination number of \(\mathrm{Cr}\) is six. A complex with \(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}\), en and…

Coordination number of \(\mathrm{Cr}\) is six. A complex with \(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}\), en and superoxide \(\mathrm{O}_{2}^{-}\)will be in the ratio to make complex \(\left[\mathrm{Cr}\left(\mathrm{C}_{2} \mathrm{O}_{4}ight)_{\mathrm{x}}(\mathrm{en})_{\mathrm{y}}\left(\mathrm{O}_{2}ight)_{\mathrm{z}}ight]^{-}:\)
  1. \(x=1, y=1, z=1\)
  2. \(\mathrm{x}=1, \mathrm{y}=1, \mathrm{z}=2\)
  3. \(x=1, y=2, z=2\)
  4. \(x=2, y=1, z=1\)

Solution

As co-ordination of \(\mathrm{Cr}\) is 6 \(\mathrm{C}_{2} \mathrm{O}_{4}^{2-} \&\) en are bidentate ligands while \(\mathrm{O}_{2}^{-}\)is unidentate so \(x=1, y=1, z=2\) \(\left[\mathrm{Cr}\left(\mathrm{C}_{2} \mathrm{O}_{4}ight)_{1}(\mathrm{en})_{1}\left(\mathrm{O}_{2}ight)_{2}ight]^{-}\) ~

Asked in: JEE-TOPICTESTS-CHEMISTRY

Practice more COORDINATION COMPOUNDS questions on Aicharya