Coordination number and oxidation state of \(\mathrm{Cr}\) in…
Coordination number and oxidation state of \(\mathrm{Cr}\) in \(\mathrm{K}_{3}\left[\mathrm{Cr}\left(\mathrm{C}_{2} \mathrm{O}_{4}ight)_{3}ight]\) are, respectively:
3 and \(+3\)
3 and 0
6 and \(+3\)
4 and \(+2\)
Solution
As oxalate is a bidentate ligand, coordination number of \(\mathrm{Cr}\) is 6 .
Since the overall charge on the complex is 0 , the sum of oxidation states of all elements in it should be equal to 0
Let the oxidation number of \(\mathrm{Cr}\) be \(\mathrm{x}\).
Therefore, \(3+x+3 \times(-2)=0\)
or, \(x=+3\)