Coolent used in car radiator is aqueous solution of ethylene glycol. In order to prevent the solution from…

Coolent used in car radiator is aqueous solution of ethylene glycol. In order to prevent the solution from freezing at $-0.3^{\circ} \mathrm{C}$. How much ethylene glycol (in g) must be added to $5 \mathrm{~kg}$ of water $?\left(\mathrm{~K}_{\mathrm{f}}=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}ight)$
  1. 50
  2. 52
  3. 62
  4. 60

Solution

$\Delta \mathrm{T}_{\mathrm{f}}=0.3^{\circ} \mathrm{C}$
$\Delta \mathrm{T}_{\mathrm{f}}=0.3^{\circ} \mathrm{C}=\frac{\mathrm{K}_{\mathrm{f}} \times \mathrm{W}_{\mathrm{B}} \times 1000}{\mathrm{M}_{\mathrm{B}} \times \mathrm{W}_{\mathrm{A}}}$
$0.3=\frac{1.86 \times \mathrm{W}_{\mathrm{B}} \times 1000}{62 \times 5000}$
$\therefore \quad \mathrm{W}_{\mathrm{B}}=50 \mathrm{~g}$
The amount used should be more than $50 \mathrm{~g}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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