Considering the Bohr model of hydrogen like atoms, the ratio of the ratio of the radius $5^{ ext {th }}$ orbit of the electron in $\mathrm{Li}^{2+}$ and $\mathrm{He}^{+}$is

Question

Considering the Bohr model of hydrogen like atoms, the ratio of the ratio of the radius $5^{	ext {th }}$ orbit of the electron in $\mathrm{Li}^{2+}$ and $\mathrm{He}^{+}$is

Aicharya · Accepted Answer

$\mathrm{r}=\mathrm{r} \cdot \frac{\mathrm{n}^2}{2}$
for $\mathrm{Li}^{2+}$
$r_5=r \cdot \frac{25}{3}$
for $\mathrm{He}^{+}$
$\begin{aligned}
& \mathrm{r}_5=\mathrm{r} \cdot \frac{25}{2} \\ & \therefore \frac{\mathrm{r}_{\mathrm{Li}^{2+}}}{\mathrm{r}_{\mathrm{He}^{+}}}=\frac{2}{3}
\end{aligned}$

Considering the Bohr model of hydrogen like atoms, the ratio of the ratio of the radius $5^{\text {th }}$…

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