Considering interference between two sources of intensities ' I ' and ' 4 I ', the intensity at a point where the phase difference is $\pi$ is $(\cos \pi=-1)$.

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Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{I}^{\prime}=\mathrm{I}_1+\mathrm{I}_2+2 \sqrt{\mathrm{I}_{\mathrm{I}} \mathrm{I}_2} \cos 	heta \ & \mathrm{I}^{\prime}=\mathrm{I}+4 \mathrm{I}+2 \sqrt{\mathrm{I} 	imes 4 \mathrm{I}}(-1) \ & \mathrm{I}^{\prime}=\mathrm{I}\end{aligned}$ .

Considering interference between two sources of intensities ' I ' and ' 4 I ', the intensity at a point…

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