Consider three boxes, each containing 10 balls labelled 1 ,   2 ,   … . ,   10 .…

Consider three boxes, each containing 10 balls labelled 1, 2, ., 10. Suppose one ball is randomly drawn from each of the boxes. Denote by ni, the label of the ball drawn from the ith box, i=1, 2, 3. Then, the number of ways in which the balls can be chosen such that n1<n2<n3 is :
  1. 240
  2. 82
  3. 120
  4. 164

Solution

Each box contains 10 balls numbered from 1 to 10.

n1,n2,n3 are numbers on the balls drawn from the box B1,B2 and B3 respectively such that n1<n2<n3.

i.e., all 3 numbers n1,n2,n3 must be different and can be arranged only in one way (increasing).

Now n1,n2,n3 can be selected in 10C3 ways.

Hence, total number of ways =10C3.1=10C3=10!3!7!=10×9×83×2=120.

Asked in: JEE Main 2019 (12 Jan Shift 1)

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