Consider the reactions (i) \(\left(\mathrm{CH}_3ight)_2 \mathrm{CH}-\mathrm{CH}_2 \mathrm{Br}…
Consider the reactions
(i) \(\left(\mathrm{CH}_3ight)_2 \mathrm{CH}-\mathrm{CH}_2 \mathrm{Br} \xrightarrow{\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}}\left(\mathrm{CH}_3ight)_2 \mathrm{CH}-\mathrm{CH}_2 \mathrm{OC}_2 \mathrm{H}_5+\mathrm{HBr}\)
(ii) \(\left(\mathrm{CH}_3ight)_2 \mathrm{CH}-\mathrm{CH}_2 \mathrm{Br} \xrightarrow{\mathrm{C}_2 \mathrm{H}_5 \mathrm{O}^{-}}\left(\mathrm{CH}_3ight)_2 \mathrm{CH} C H_2 \mathrm{OC}_2 \mathrm{H}_5+\mathrm{Br}^{-}\)
The mechanism of reactions (i) & (ii) are respectively
\(\mathrm{S}_{\mathrm{N}} 1\) and \(\mathrm{S}_{\mathrm{N}} 2\)
\(\mathrm{S}_{\mathrm{N}} 1\) and \(\mathrm{S}_{\mathrm{N}} 1\)
\(\mathrm{S}_{\mathrm{N}} 2\) and \(\mathrm{S}_{\mathrm{N}} 2\)
\(\mathrm{S}_{\mathrm{N}} 2\) and \(\mathrm{S}_{\mathrm{N}} 1\)
Solution
\(\mathrm{S}_{\mathrm{N}} 2\) and \(\mathrm{S}_{\mathrm{N}} 2\)
Since rearrangement do not occur in the given nucleophilic substitution reactions, therefore carbocations are not the intermediate in these reactions. Thus both the reactions occur by \(\mathrm{S}_{\mathrm{N}} 2\) mechanism.