Consider the parabola y 2 = 4 x . Let S be the focus of the parabola. A pair of tangents drawn to the…

Consider the parabola y2=4x. Let S be the focus of the parabola. A pair of tangents drawn to the parabola from the point P=-2,1 meet the parabola at P1 and P2. Let Q1 and Q2 be points on the lines SP1 and SP2 respectively such that PQ1 is perpendicular to SP1 and PQ2 is perpendicular to SP2. Then, which of the following is/are TRUE?
  1. SQ1=2
  2. Q1Q2=3105
  3. PQ1=3
  4. SQ2=1

Solution

On plotting the diagram of the given value we have,

Now let P1t2,2t then tangent at P1 will be ty=x+t2

Since it passes through -2,1

 t2-t-2=0

t=2,-1

So, we get points P14,4 and P21,-2

Now finding the equation of SP1:4x-3y-4=0

And equation of SP2:x-1=0

Now finding the point by foot of point on line formula,

Q1:x1+24=y1-1-3=--8-3-425=35

We get x1=25,y1=-45

Similarly for Q2=1,1

Now using the distance formula we get, SQ1=1-252+452=1

Q1Q2=925+8125=9025=3105

PQ1=14425+8125=3

SQ2=1.

Asked in: JEE Advanced 2022 (Paper 1)

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