Consider the nuclear fission, Ne 20 → 2 He 4 + C 12 . Given that the binding energy/nucleon of Ne 20 ,…

Consider the nuclear fission, Ne20→2He4+C12. Given that the binding energy/nucleon of Ne20, He4 and C12 are 8.03 MeV, 7.86 MeV, respectively. Identify the correct statement:
  1. Energy of 12.4 MeV will be supplied.
  2. Energy of 9.72 MeV has to be supplied.
  3. Energy of 3.6 MeV will be released.
  4. 8.3 MeV energy will be released.

Solution

Q=Ef-Ei
=12×7.86+4×7.07+4×7.07-(20×8.03)
Q=-9.72 MeV

Asked in: JEE Main 2019 (10 Jan Shift 2)

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