Consider the nitration of benzene using mixed conc. H 2 S O 4 and H N O 3 . If a large amount of K H S O 4…

Consider the nitration of benzene using mixed conc. H2SO4 and HNO3 . If a large amount of KHSO4 is added to the mixture, the rate of nitration will be:
  1. Faster
  2. Slower
  3. Unchanged
  4. Doubled

Solution


Q= Product Reactant as product increase Q>K
Q has became equal to K product has to decrease so equilibrium will shift backward direction.
If we add KHS O 4 − ,  conc.HS O 4 − increases, equilibrium shifts backward.

Asked in: NEET 2016 (Phase 1)

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