Consider the ions/molecule O 2 + , O 2 , O 2 - , O 2 2 - . For increasing bond order the correct option is

Consider the ions/molecule O2+,O2,O2-,O22-. For increasing bond order the correct option is
  1. O2-<O22-<O2<O2+
  2. O2-<O22-<O2+<O2
  3. O2-<O2+<O22-<O2
  4. O22-<O2-<O2<O2+
     

Solution

Bond order =number of bonding e--number of antibonding e-2

Electronic configuration of O2, O2+, O2- and O2-2 are:

O2=σ1s2σ1s2*σ2s2σ2s2*σ2px2π2py2=π2pz2π2py1*=π2pz1* (Bond order=2)O2+=σ1s2σ1s2*σ2s2σ2s2*σ2px2π2py2=π2pz2π2py1*=π2pz0* (Bond order=2.5)O2-=σ1s2σ1s2*σ2s2σ2s2*σ2px2π2py2=π2pz2π2py2*=π2pz1* (Bond order=1.5)O2-2=σ1s2σ1s2*σ2s2σ2s2*σ2px2π2py2=π2pz2π2py2*=π2pz2* (Bond order=1)

Asked in: JEE Main 2022 (26 Jun Shift 1)

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