Consider the following statements: I. In diamond, each carbon atom is $s p^3$-hybridised. II. Graphite has…

Consider the following statements: I. In diamond, each carbon atom is $s p^3$-hybridised. II. Graphite has planar hexagonal layers of carbon atoms. III. Silicones being surrounded by non-polar alkyl groups are water repelling in nature IV. The order of catenation in group 14 elements is $\mathrm{Si}>\mathrm{C}>\mathrm{Sn}>\mathrm{Ge}>\mathrm{Pb}$. The correct statements are
  1. I, II, III
  2. II, III, IV
  3. I, II, IV
  4. I, III, IV

Solution

(I, II) In diamond, hybridisation of carbon is $s p^3$ and graphite has planar hexagonal layer of $\mathrm{C}$-atoms. The hybridisation of each $\mathrm{C}$-atom in graphite is $s p^2$. (III) Silicones are organo-silicon polymers formed from inorganic and organic monomer having chemical formula $\left(R_2 \mathrm{SiO}ight)_n$, due to non-polar alkyl group, silicones are water repelling in nature. (IV) The catenation tendency in group 14 elements decreases due to decrease in element bond strength. Thus, the correct order is $$ \mathrm{C}>>\mathrm{Si}>\mathrm{Ge} \approx \mathrm{Sn} $$ Hence, statement (IV) is incorrect. Thus, option (a) is correct. ^

Asked in: JEE-TOPICTESTS-CHEMISTRY

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