Consider the following reduction processes:

${Zn}^{2 +} + 2 e^{-} \to Zn (s); E^{o} = - 0 .76 V$

${Ca}^{2 +} + 2 e^{-} \to Ca (s); E^{o} = - 2 .87 V$

${Mg}^{2 +} + 2 e^{-} \to Mg (s); E^{o} = - 2 .36 V$

${Ni}^{2 +} + 2 e^{-} \to Ni (s); E^{o} = - 0 .25 V$

The reducing power of the metals increases in the order:

Question

Consider the following reduction processes:

{Zn}^{2 +} + 2 e^{-} \to Zn (s); E^{o} = - 0 .76 V

{Ca}^{2 +} + 2 e^{-} \to Ca (s); E^{o} = - 2 .87 V

{Mg}^{2 +} + 2 e^{-} \to Mg (s); E^{o} = - 2 .36 V

{Ni}^{2 +} + 2 e^{-} \to Ni (s); E^{o} = - 0 .25 V

The reducing power of the metals increases in the order:

Aicharya · Accepted Answer

Lower the standard reduction potential more will be the reducing power i.e gets self oxidised. Therefore the correct order is: Ni &#60; Zn &#60; Mg &#60; Ca

Consider the following reduction processes: Zn 2 + + 2 e - → Zn ( s ) ; E o = - 0 .76   V Ca 2 +…

Solution

Consider the following reduction processes: Zn 2 + + 2 e - &#8594; Zn ( s ) ; E o = - 0 .76 &#8201; V Ca 2 +…

Solution

Consider the following reduction processes: Zn 2 + + 2 e - → Zn ( s ) ; E o = - 0 .76 V Ca 2 +…