Consider the following reaction: x   MnO 4 - + y   C 2 O 4 2 - + zH + ⟶ x   Mn 2 + + 2…

Consider the following reaction:
x MnO4-+y C2O42-+zH+⟶x Mn2++2y CO2+z2H2O 
The values of x, y and z in the reaction are, respectively:
  1. 2,5 and 16
  2. 5,2 and 8
  3. 5,2 and 16
  4. 2,5 and 8

Solution

C 2 O 4 2 - ⟶ 2 CO 2 + 2 e - ] × 5 MnO 4 - + 8 H + + 5 e- ⟶ Mn 2 + + 4 H 2 O ] × 2
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2 MnO 4 - + 1 6 H + + 5 C 2 O 4 2 - ⟶ 1 0 CO 2 + 2 Mn 2 + + 8 H 2 O

MnO 4 - ⇒ x = 2

C 2 O 4 2 - ⇒ y = 5

H + ⇒ z = 1 6

Asked in: JEE Main 2013 (07 Apr)

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