Consider the following reactions $\begin{aligned} & \mathrm{CrO}_2 \mathrm{Cl}_{2(\text { Vapour…

Consider the following reactions

$\begin{aligned}
& \mathrm{CrO}_2 \mathrm{Cl}_{2(\text { Vapour })}+\mathrm{NaOH} \rightarrow \mathrm{~B}+\mathrm{NaCl}+\mathrm{H}_2 \mathrm{O} \\
& \mathrm{~B}+\mathrm{H}^{+} \rightarrow \mathrm{C}+\mathrm{H}_2 \mathrm{O}
\end{aligned}$
The number of terminal ' O ' present in the compound ' C ' is ______.

Solution

$\begin{aligned} & \mathrm{Cr}_2 \mathrm{O}_7^{2-}+\mathrm{NaCl}+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow \mathrm{CrO}_2 \mathrm{Cl}_2 \\ & \mathrm{CrO}_2 \mathrm{Cl}_2(\text { Vapour })+\mathrm{NaOH} \rightarrow \mathrm{Na}_2 \mathrm{CrO}_4+\mathrm{NaCl}+\mathrm{H}_2 \mathrm{O}\end{aligned}$

$\mathrm{Na}_2 \mathrm{Cr}_2 \mathrm{O}_7 \rightarrow 2 \mathrm{Na}^{\oplus}+\mathrm{Cr}_2 \mathrm{O}_7^{2-}$
No of terminal "O" = 6

Asked in: JEE Main 2025 (03 Apr Shift 1)

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