Consider the following reactions $\mathrm{C}_2 \mathrm{H}_2+\mathrm{H}_2 \mathrm{O} \xrightarrow[333…
- $\mathrm{CH}_3 \mathrm{COCl}+\mathrm{H}_2 \xrightarrow{\mathrm{Pd} / \mathrm{BaSO}_4}$
- $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH} \xrightarrow{\mathrm{Cu} / 573 \mathrm{~K}}$
- $\mathrm{CH}_3 \mathrm{CN}+\mathrm{SnCl}_2+\mathrm{HCl} \longrightarrow \mathrm{X} \xrightarrow{\mathrm{H}_3 \mathrm{O}^{+}}$
- $\mathrm{CH}_3 \mathrm{COOH} \xrightarrow[\text { (ii) } \mathrm{H}_2 \mathrm{O}]{\text { (i) } \mathrm{Lill}_4 / \text { ether }}$
Solution

Rosenmund Reaction : $\mathrm{CH}_3 \mathrm{COCl}+\mathrm{H}_2 \xrightarrow{\mathrm{Pd} / \mathrm{BaSO}_4} \mathrm{CH}_3 \mathrm{CHO}+\mathrm{HCl}$ Dehydrogenation: $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH} \xrightarrow{\mathrm{Cu} / 573 \mathrm{~K}} \mathrm{CH}_3 \mathrm{CHO}+\mathrm{H}_2$ Stephen Reduction :

Reduction : $\mathrm{CH}_3 \mathrm{COOH} \xrightarrow[\text { (ii) } \mathrm{H}_2 \mathrm{O}]{\text { (i) } \mathrm{LiAlH}_4 / \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}}$
Asked in: AP EAMCET 2024 (22 May Shift 2)
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