Consider the following reactions (unbalanced) Z n + H o t   c o n c .   H 2 S O 4 → G + R +…
Consider the following reactions (unbalanced)
Choose the correct option(s).
- The oxidation state of in is
- Bond order of is in its ground state
- is dirty white in colour
- is a -shaped molecule
Solution
\(\begin{aligned}
& \underset{\text { Zn }}{\mathrm{Zn}}+\underset{\text { conc. }}{\mathrm{H}_2 \mathrm{SO}_4} \longrightarrow \underset{(\mathrm{G})}{\mathrm{ZnSO}_4}+\underset{(\mathrm{R})}{\mathrm{SO}_2}+\underset{(\mathrm{X})}{\mathrm{H}_2 \mathrm{O}} \\
& \underset{\text { conc. }}{\mathrm{Zn}}+\underset{(\mathrm{T})}{\mathrm{NaOH}} \longrightarrow \underset{(\mathrm{Q})}{\mathrm{Na}_2\left[\mathrm{ZnO}_2\right]}+\underset{2}{\mathrm{H}_2}
\end{aligned}\)
\(\underset{\text { (G) }}{\mathrm{ZnSO}_4}+\underbrace{\mathrm{H}_2 \mathrm{~S}+\mathrm{NH}_4 \mathrm{OH}}_{\substack{\text { group-IV } \\ \text { reagent }}}\)
\(\longrightarrow \underset{(\mathrm{Z})}{\mathrm{ZnS} \downarrow}+\underset{(\mathrm{Y})}{\left(\mathrm{NH}_4\right)_2 \mathrm{SO}_4}+\underset{(\mathrm{X})}{\mathrm{H}_2 \mathrm{C}}\)
\(\mathrm{SO}_2(\mathrm{R})\) is V-shaped.
\(\mathrm{Z} n \mathrm{~S}(\mathrm{Z})\) is dirty white gelatinous ppt.
Bond order in \(\mathrm{H}_2(\mathrm{Q})\) is 1
Asked in: JEE Advanced 2019 (Paper 2)
Practice more Transition and Inner Transition Elements questions on Aicharya