Consider the following reactions (unbalanced) Z n + H o t   c o n c .   H 2 S O 4 → G + R +…

Consider the following reactions (unbalanced)
Zn+Hot conc. H2SO4G+R+X
Zn+conc. NaOHT+Q
G+H2S+NH4OHZa precipitate+X+Y
Choose the correct option(s).
  1. The oxidation state of Zn in T is +1
  2. Bond order of Q is 1 in its ground state
  3. Z is dirty white in colour
  4. R is a V -shaped molecule

Solution

\(\begin{aligned} & \underset{\text { Zn }}{\mathrm{Zn}}+\underset{\text { conc. }}{\mathrm{H}_2 \mathrm{SO}_4} \longrightarrow \underset{(\mathrm{G})}{\mathrm{ZnSO}_4}+\underset{(\mathrm{R})}{\mathrm{SO}_2}+\underset{(\mathrm{X})}{\mathrm{H}_2 \mathrm{O}} \\ & \underset{\text { conc. }}{\mathrm{Zn}}+\underset{(\mathrm{T})}{\mathrm{NaOH}} \longrightarrow \underset{(\mathrm{Q})}{\mathrm{Na}_2\left[\mathrm{ZnO}_2\right]}+\underset{2}{\mathrm{H}_2} \end{aligned}\) \(\underset{\text { (G) }}{\mathrm{ZnSO}_4}+\underbrace{\mathrm{H}_2 \mathrm{~S}+\mathrm{NH}_4 \mathrm{OH}}_{\substack{\text { group-IV } \\ \text { reagent }}}\) \(\longrightarrow \underset{(\mathrm{Z})}{\mathrm{ZnS} \downarrow}+\underset{(\mathrm{Y})}{\left(\mathrm{NH}_4\right)_2 \mathrm{SO}_4}+\underset{(\mathrm{X})}{\mathrm{H}_2 \mathrm{C}}\) \(\mathrm{SO}_2(\mathrm{R})\) is V-shaped. \(\mathrm{Z} n \mathrm{~S}(\mathrm{Z})\) is dirty white gelatinous ppt. Bond order in \(\mathrm{H}_2(\mathrm{Q})\) is 1

Asked in: JEE Advanced 2019 (Paper 2)

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