Consider the following reaction MnO 4 - + 8 H + + 5 e - → Mn + 2 + 4 H 2 O   , E ° = 1 . 51…

Consider the following reaction

MnO4-+8H++5e-→Mn+2+4H2O ,E°=1.51 V

The quantity of electricity required in Faraday to reduce five moles of MnO4- is              

Solution

For this balanced reaction, the change in oxidation number of the metal ion is Mn+7 →Mn+2.

Therefore one mole Mn required 5 Faraday

Hence, for five mole Mn required 25 Faraday.

Asked in: JEE Main 2021 (26 Feb Shift 1)

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