Consider the following reaction, the product $Z$, is

Consider the following reaction,
the product $Z$, is

1. $\mathrm{CH}_2=\mathrm{CH}_2$
2. $\mathrm{CH}_3 \mathrm{CH}_2-\mathrm{O}-\mathrm{CH}_2-\mathrm{CH}_3$
3. $\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{O}-\mathrm{SO}_3 \mathrm{H}$
4. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}$

Solution

Key Idea (i) $\mathrm{PBr}_3$ is a halogenating agent, ie, converts $-\mathrm{OH}$ group into $-\mathrm{Br}$. (ii) Alc. $\mathrm{KOH}$ is a dehydrohalogenating agent. (iii) $\mathrm{H}_2 \mathrm{SO}_4$ and $\mathrm{H}_2 \mathrm{O}$ converts an olefin into alcohol.

Asked in: NEET 2009 (Screening)

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