Consider the following reaction \[ \mathrm{A}+\mathrm{B} \rightarrow \mathrm{C} \] The time taken for…
Consider the following reaction
\[
\mathrm{A}+\mathrm{B} \rightarrow \mathrm{C}
\]
The time taken for \(\mathrm{A}\) to become \(1 / 4^{\text {th }}\) of its initial concentration is twice the time taken to become \(1 / 2\) of the same. Also, when the change of concentration of \(B\) is plotted against time, the resulting graph gives a straight line with a negative slope and a positive intercept on the concentration axis.
The overall order of the reaction is _______
Solution
For $1^{\text {st }}$ order reaction
$75 \% \text { life }=2 \times 50 \% \text { life }$ So order with respect to A will be first order.
So order with respect to B will be zero. Overall order of reaction $=1+0=1$
