Consider the following logic circuit. The output is $\mathrm{Y}=0$ when :

Consider the following logic circuit.

The output is $\mathrm{Y}=0$ when :

1. $\mathrm{A}=1$ and $\mathrm{B}=1$
2. $\mathrm{A}=0$ and $\mathrm{B}=1$
3. $\mathrm{A}=1$ and $\mathrm{B}=0$
4. $\mathrm{A}=0$ and $\mathrm{B}=0$

Solution

$\begin{aligned}
& \mathrm{Y}_1=\mathrm{A} \cdot \mathrm{~B}, \mathrm{Y}_2=\overline{\mathrm{A}}+\mathrm{B} \\ & \mathrm{Y}=\overline{\mathrm{Y}_1 \cdot \mathrm{Y}_2}=\overline{\mathrm{Y}}_1+\overline{\mathrm{Y}}_2 \\ & \mathrm{Y}=\overline{\mathrm{A} \cdot \mathrm{~B}}+\overline{\mathrm{A}+\mathrm{B}} \\ & \mathrm{Y}=\overline{\mathrm{A}}+\overline{\mathrm{B}}+\mathrm{A} \cdot \overline{\mathrm{~B}}
\end{aligned}$
$\begin{array}{|c|c|c|} \hline A & B & Y \\ \hline 0 & 0 & 1 \\ \hline 1 & 0 & 1 \\ \hline 0 & 1 & 1 \\ \hline 1 & 1 & 0 \\ \hline \end{array}$

Asked in: JEE Main 2025 (07 Apr Shift 2)

Practice more Semiconductors questions on Aicharya