Consider the following complexes. $\left[\mathrm{MA}_{6}ight],\left[\mathrm{MA}_{5} \mathrm{~B}ight]…
Consider the following complexes.
$\left[\mathrm{MA}_{6}ight],\left[\mathrm{MA}_{5} \mathrm{~B}ight],\left[\mathrm{MA}_{2} \mathrm{~B}_{4}ight],\left[\mathrm{MA}_{3} \mathrm{~B}_{3}ight]\left[\mathrm{MA}_{4} \mathrm{~B}_{2}ight]$
Find the number of complexes will show geometrical isomerism.
1
3
4
2
Solution
$\left[\mathrm{MA}_{6}ight]$ No. of geometrical isomers $\left[\mathrm{MA}_{5} \mathrm{~B}ight]$ No. of geometrical isomers $\left.\begin{array}{l}{\left[\mathrm{MA}_{2} \mathrm{~B}_{4}ight]} \\ {\left[\mathrm{MA}_{3} \mathrm{~B}_{3}ight]} \\ {\left[\mathrm{MA}_{4} \mathrm{~B}_{2}ight]}\end{array}ight\}$ Each show 2 geometical isomers
Thus, 3 complexes will show geometrical isomerism.