Consider the following chemical reaction.
$CH \equiv CH \frac{1) Red hot Fe tube, 873 K}{2) CO, HCl, {AlCl}_{3}} > Product$
The number of ${sp}^{2}$ hybridized carbon atom(s) present in the product is

Question

Consider the following chemical reaction.

CH \equiv CH \frac{1) Red hot Fe tube, 873 K}{2) CO, HCl, {AlCl}_{3}} > Product

The number of

{sp}^{2}

hybridized carbon atom(s) present in the product is

Aicharya · Accepted Answer

In benzaldehyde total number of sp 2 ' C ' are 7 &#160; .

Consider the following chemical reaction. CH ≡ CH   1 )   Red   hot   Fe  …