Consider the following cell reaction, $ \begin{array}{cc} & 2 \mathrm{Fe}(\mathrm{s})+\mathrm{O}_2(g)+4 \mathrm{H}^{+}(a q) \longrightarrow \ & 2 \mathrm{Fe}^{2+}(a q)+2 \mathrm{H}_2 \mathrm{O}(l), E^{\circ}=1.67 \mathrm{~V} \ ext { At } & {\left[\mathrm{Fe}^{2+} ight]=10^{-3} \mathrm{M},…

Question

Consider the following cell reaction, $ \begin{array}{cc} & 2 \mathrm{Fe}(\mathrm{s})+\mathrm{O}_2(g)+4 \mathrm{H}^{+}(a q) \longrightarrow \ & 2 \mathrm{Fe}^{2+}(a q)+2 \mathrm{H}_2 \mathrm{O}(l), E^{\circ}=1.67 \mathrm{~V} \ 	ext { At } & {\left[\mathrm{Fe}^{2+}ight]=10^{-3} \mathrm{M}, \mathrm{P}\left(\mathrm{O}_2ight)=0.1 \mathrm{~atm}} \end{array} $ and $\mathrm{pH}=3$, the cell potential at $25^{\circ} \mathrm{C}$ is

Aicharya · Accepted Answer

The half reactions are $\mathrm{Fe}(s) \longrightarrow \mathrm{Fe}^{2+}(\mathrm{aq})+2 e^{-} 	imes 2$ $ \begin{array}{r} \mathrm{O}_2(g)+4 \mathrm{H}^{+}+4 e^{-} \longrightarrow 2 \mathrm{H}_2 \mathrm{O}+2 \mathrm{Fe}(s) \ +\mathrm{O}_2(g)+4 \mathrm{H}^{+} \longrightarrow 2 \mathrm{Fe}^{2+}(a q)+2 \mathrm{H}{ }_2 \mathrm{O}(l) \ E=E^{\circ}-\frac{0.059}{4} \log \frac{\left(10^{-3}ight)^2}{\left(10^{-3}ight)^4(0.1)}=1.57 \mathrm{~V} \end{array} $

Consider the following cell reaction, $ \begin{array}{cc} & 2 \mathrm{Fe}(\mathrm{s})+\mathrm{O}_2(g)+4…

Solution