Consider the following bromides : The correct order of $\mathrm{S}_{\mathrm{N}} 1$ reactivity is
Consider the following bromides :
The correct order of $\mathrm{S}_{\mathrm{N}} 1$ reactivity is
$B>C>A$
$B>A>C$
$C>B>A$
$A>B>C$
Solution
$\mathrm{S}_{\mathrm{N}} 1$ proceeds via carbocation intermediate, the most stable one forming the product faster. Hence reactivity order for $\mathrm{A}, \mathrm{B}, \mathrm{C}$ depends on stability of carbocation created.
