Consider the consecutive reactions :
\(A \stackrel{k=2 \times 10^{-5} \mathrm{~s}^{-1}}{\longrightarrow} B \stackrel{k=8 \times 10^{-6} \mathrm{~s}^{-1}}{\longrightarrow} C \stackrel{k=3 \times 10^{-3} \mathrm{~s}^{-1}}{\longrightarrow} D\)
The rate determining step of the reaction is :
$A ightarrow B$
$C ightarrow D$
$B ightarrow C$
$A ightarrow D$
Solution
The slowest step determines the rate. B $\to$ C is the slowest and thus the rate determining step.
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