Consider, PF 5 , BrF 5 , PCl 3 , SF 6 , ICl 4 - , ClF 3 and IF 5 Amongst the above molecule(s) ion(s), the number of molecule(s)/ion(s) having sp 3 d 2 hybridisation is

Question

Aicharya · Accepted Answer

Number of hybrid orbitals = Number of bond pair + number of lone pair on central atom.
To have ${sp}^{3} d^{2}$ hybridisation there should be total of 6 (bond pairs + lone pairs). The structure in such case will be octahedral or its derivative structures.

Consider, PF 5 , BrF 5 , PCl 3 , SF 6 , ICl 4 - , ClF 3 and IF 5 Amongst the above molecule(s) ion(s), the…

Solution