Consider an expanding sphere of instantaneous radius R whose total mass remains constant. The expansion is…

Consider an expanding sphere of instantaneous radius R whose total mass remains constant. The expansion is such that the instantaneous density ρ remains uniform throughout the volume. The rate of fractional change in density 1ρdρdt is constant. The velocity v of any point on the surface of the expanding sphere is proportional to
  1. R3
  2. 1R
  3. R
  4. R23

Solution

$\rho = \frac{m}{v} = \frac{3m}{4\pi R^3}$ $\Rightarrow \frac{1}{\rho} \frac{d\rho}{dt} = -\frac{3}{R} \frac{dR}{dt}$ Since $\Rightarrow \frac{1}{\rho} \frac{d\rho}{dt}$ is constant $\therefore \frac{dR}{dt} \propto R$

Asked in: JEE Advanced 2017 (Paper 2)

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