Consider an elliptically shaped rail PQ in the vertical plane with $O P = 3 m$ and $O Q = 4 m$ . A block of mass 1 kg is pulled along the rail from P to Q with a force of 18 N, which is always parallel to line PQ (see the figure given). Assuming no frictional losses, the kinetic energy of the block when it reaches Q is $(n \times 10)$ Joules. The value of n is (take acceleration due to gravity = $10 m s^{- 2}$ )

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Aicharya · Accepted Answer

Using work energy theorem W m g + W F = ∆ K E - m g h + F d = ∆ K E - 1 × 10 × 4 + 18 5 = ∆ K E ∆ K E = 50 ∴ n = 5 !

Consider an elliptically shaped rail PQ in the vertical plane with O P = 3 m and O Q = 4 m . A block of mass…

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