Consider an elementary reaction $\mathrm{A}(\mathrm{g})+\mathrm{B}(\mathrm{g}) \rightarrow…
$\mathrm{A}(\mathrm{g})+\mathrm{B}(\mathrm{g}) \rightarrow \mathrm{C}(\mathrm{g})+\mathrm{D}(\mathrm{g})$
If the volume of reaction mixture is suddenly reduced to $\frac{1}{3}$ of its initial volume, the reaction rate will become ' $x$ ' times of the original reaction rate. The value of $x$ is :
- $3$
- $\frac{1}{9}$
- $9$
- $\frac{1}{3}$
Solution
$\text { Rate }=k[A]^1[B]^1$
When V is reduced to $\frac{1}{3} \mathrm{~V}$, concentration will be tripled.
Hence, rate $=9 \times(\text { rate })_{\text {initial }}$
$x=9$
Asked in: JEE Main 2025 (28 Jan Shift 2)