Consider a drop of rain water having mass 1 g falling from a height of 1 km . It hits the ground with a speed of 50 m s - 1 . Take g constant with a value 10 m s - 2 . The work done by the (i) gravitational force and the (ii) resistive force of air is

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Aicharya · Accepted Answer

By Work-Energy Theorem W g + W a = K f - K i m g h + W a = 1 2 m v 2 - 0 10 - 3 × 10 × 10 3 + w a = 1 2 × 10 - 3 × 50 2 W a = - 8.75 J work done due to gravity = mgh = 10 − 3 × 10 × 10 3 = 10 J

Consider a drop of rain water having mass 1 g falling from a height of 1 km . It hits the ground with a…

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