Consider a disc of mass 5 kg , radius 2 m , rotating with angular velocity of 10 rad s - 1 about an axis perpendicular to the plane of rotation. An identical disc is kept gently over the rotating disc along the same axis. The energy dissipated so that both the discs continue to rotate together…

Question

Consider a disc of mass 5 kg , radius 2 m , rotating with angular velocity of 10 rad s - 1 about an axis perpendicular to the plane of rotation. An identical disc is kept gently over the rotating disc along the same axis. The energy dissipated so that both the discs continue to rotate together without slipping is _________ J .

Aicharya · Accepted Answer

Initial angular momentum, L i = I ω i = M R 2 2 · ω = 100 kg m 2 s - 1 Initial kinetic energy, E i = 1 2 · M R 2 2 · ω 2 = 500 J From conservation of angular momentum, we can write L → i = L → f ⇒ 100 = 2 I ω f ⇒ ω f = 5 rad s - 1 E f = 2 × 1 2 · 5 ( 2 ) 2 2 · ( 5 ) 2 = 250 J Therefore, required energy loss Δ E = 250 J

Consider a disc of mass 5 kg , radius 2 m , rotating with angular velocity of 10 rad s - 1 about an axis…

Solution