Consider a cylinder of mass M resting on a rough horizontal rug that is pulled out from under it with…

Consider a cylinder of mass M resting on a rough horizontal rug that is pulled out from under it with acceleration 'a' perpendicular to the axis of the cylinder. What is Ffriction at point P ? It is assumed that the cylinder does not slip.
  1. Ma
  2. Ma 2
  3. Ma 3
  4. Mg

Solution



For no slipping at P
a 1 + α R = a    →    (1)



f = Ma 1 = M a - α R    →    (2)

f. R = I · α = MR 2 2 · α    →    (3)

Solve the equations (2) and (3)

f = Ma 3

Asked in: JEE Main 2014 (19 Apr Online)

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