Consider a 20   kg uniform circular disk of radius 0 . 2   m . It is pin supported at its center…

Consider a 20 kg uniform circular disk of radius 0.2 m. It is pin supported at its center and is at rest initially. The disk is acted upon by a constant force F=20 N through a massless string wrapped around its periphery as shown in the figure.

Suppose the disk makes n number of revolutions to attain an angular speed of 50 rad s-1. The value of n, to the nearest integer, is _______ .

[Given : In one complete revolution, the disk rotates by 6.28 rad]

Solution

α=τI=F.R.mR2/2=2 FmR

α=2×20020×0.2=10 rad/s2

ω2=ω02+2αΔθ

502=02+210ΔθΔθ=250020
Δθ=125 rad

No. of =1252π20 revolution

Asked in: JEE Main 2021 (16 Mar Shift 1)

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