Conjugate of $\sqrt{a} + \sqrt{b}$ is
Conjugate of $\sqrt{a} + \sqrt{b}$ is
- $\sqrt{a} - \sqrt{b}$
- $\sqrt{a} + \sqrt{b}$
- $\sqrt{a} \cdot \sqrt{b}$
- $\sqrt{a + b}$
Solution
Standard conjugate definition.
Asked in: MH-SSC-9
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