Conjugate of $2 + \sqrt{3}$ is

Conjugate of $2 + \sqrt{3}$ is
  1. $2 - \sqrt{3}$
  2. $2 + \sqrt{3}$
  3. $\sqrt{3} - 2$
  4. $-2 - \sqrt{3}$

Solution

For $a + \sqrt{b}$, conjugate is $a - \sqrt{b}$.

Asked in: MH-SSC-9

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