$n$ conducting wires of same dimensions but having restivities $1,2,3, . . n$ are connected in series. The…
$n$ conducting wires of same dimensions but having restivities $1,2,3, . . n$ are connected in series. The equivalent resistivity of the combination is
$1 \frac{n(n+1)}{2}$
$\frac{n+1}{2}$
$\frac{n+2}{2 n}$
$\frac{2 n}{n+1}$
Solution
Resistivity of the combination
$
\begin{aligned}
=(1+2+3+\ldots+n)
=\frac{n(n+1)}{2}
\end{aligned}
$