$\mathbf{A}$ conducting disk is of radius $R$ is rotating with an angular velocity $\omega$ allowing the fact that electrons are the current carriers in conductor, the potential difference between the centre of the disc and edge is (mass and charge of electron is $m$ and $e$ and neglect gravity)

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Aicharya · Accepted Answer

Centripetal force on electron at distance $r$ from centre of disc.
$\begin{aligned}
& m \omega^{2} r=e E \Rightarrow E=\frac{m \omega^{2} r}{e} \\
\Rightarrow \quad & \frac{d V}{d r}=-\frac{m \omega^{2} r}{e} \\
\Rightarrow \quad & V=-\frac{m \omega^{2}}{e} \int_{0}^{R} r d r=-\frac{m \omega^{2} R^{2}}{2 e}
\end{aligned}$

$\mathbf{A}$ conducting disk is of radius $R$ is rotating with an angular velocity $\omega$ allowing the…

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