Concentrated $\mathrm{H}_{2} \mathrm{SO}_{4}$ reacts with $\mathrm{PCl}_{5}$ to produce
Concentrated $\mathrm{H}_{2} \mathrm{SO}_{4}$ reacts with $\mathrm{PCl}_{5}$ to produce
$\mathrm{HClO}_{2}$
$\mathrm{SO}_{2} \mathrm{Cl}_{2}$
$\mathrm{SOCl}_{2}$
$\mathrm{HClO}_{4}$
Solution
When excess of $\mathrm{Pa}_{5}$ reacts with conc. $\mathrm{H}_{2} \mathrm{SO}_{4}$, it gives suphuryl chloride $\left(\mathrm{SO}_{2} \mathrm{Cl}_{2}\right)$ as product
