Concentrated nitric acid is labelled as $75 \%$ by mass. The volume in mL of the solution which contains 30…
____.
Given : Density of nitric acid solution is $1.25 \mathrm{~g} / \mathrm{mL}$.
- $40$
- $32$
- $45$
- $55$
Solution
$\because \quad 75 \mathrm{~g} \mathrm{HNO}_3$ in 100 g solution.
$\therefore \quad 30 \mathrm{~g} \mathrm{HNO}_3$ in $\frac{100}{75} \times 30 \mathrm{~g}$ solution.
$\begin{aligned}
& \mathrm{m}_{\text {solution }}=\frac{100 \times 30}{75} \mathrm{~g} \\
\because \quad & \mathrm{~V}_{\text {sol }}=\frac{\mathrm{m}_{\text {sol }}}{\mathrm{d}_{\text {sol }}}=\frac{100 \times 30}{75 \times 1.25}=32 \mathrm{~mL}
\end{aligned}$
Asked in: JEE Main 2025 (28 Jan Shift 2)
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