Compound $A$ is prepared by the electrolysis of aqueous solution of $B$ using Castner- Kellner cell with…
Compound $A$ is prepared by the electrolysis of aqueous solution of $B$ using Castner- Kellner cell with mercury as cathode and carbon as anode. $A$ and $B$ respectively are
NaOH, NaCl
NaCl, NaOH
$\mathrm{NaHCO}_3, \mathrm{NaOH}$
$\mathrm{Na}_2 \mathrm{CO}_3, \mathrm{NH}_3$
Solution
In Castner - Kellner cell, Reaction at anode is
$
\mathrm{Cl}^{-} \longrightarrow \frac{1}{2} \mathrm{Cl}_2+e^{-}
$
Reaction cathode is
$
\begin{aligned}
\mathrm{Na}^{+}+e^{-} & \longrightarrow \mathrm{Na} \\
2 \mathrm{H}_2 \mathrm{O}+2 e^{-} & \longrightarrow 2 \mathrm{OH}^{-}+\mathrm{H}_2 \uparrow
\end{aligned}
$
Hence, in Castner-Kellner cell $\mathrm{NaOH}$ is produced by $\mathrm{NaCl}$ solution.
Hence, option (a) is correct