$\mathrm{A}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{B}+\mathrm{HCl}$ $\mathrm{B}+\mathrm{H}_{2}…
$\mathrm{B}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{C}+\mathrm{HCl}$
Compound $(\mathrm{A}),(\mathrm{B})$ and $(\mathrm{C})$ will be respectively
- $\mathrm{PCl}_{5}, \mathrm{POCl}_{3}, \mathrm{H}_{3} \mathrm{PO}_{3}$
- $\mathrm{PCl}_{5}, \mathrm{POCl}_{3}, \mathrm{H}_{3} \mathrm{PO}_{4}$
- $\mathrm{SOCl}_{2}, \mathrm{POCl}_{3}, \mathrm{H}_{3} \mathrm{PO}_{3}$
- $\mathrm{PCl}_{3}, \mathrm{POCl}_{3}, \mathrm{H}_{3} \mathrm{PO}_{4}$
Solution
,Asked in: JEE-TOPICTESTS-CHEMISTRY
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