Column I Column II ( A ) In R 2 , if the magnitude of the projection vector of the vector α i ^ + &#946…

Column I Column II
(A) In R2 , if the magnitude of the projection vector of the vector αi^+βj^  on 3 i^+ j^ is 3 and if α=2+ 3 β, then possible value (s) of |α| is (are) P 1
(B) Let a and b be real numbers such that the function fx= -3ax2-2,x<1bx+a2,x 1 is differentiable for all xR. Then possible value (s) of a is (are) Q 2
(C) Let ω 1 be a complex cube roots of unity. If 3-3ω+2ω24n+3 + 2+3ω-3ω24n+3+ -3+2ω+3ω24n+3=0 then possible value (s) of n is (are) R 3
(D) Let the harmonic mean of two positive real numbers a and b 4. If q is a positive real number such that a, 5, q, b is an arithmetic progression, then the value (s) of |q – a| is (are) S 4
    (T) 5
  1. a-t;b-t;c-q;d-s;
  2. a-s,t;b-r,s,t;c-q,r,s;d-t;
  3. a-p,q;b-p,q;c-p,q,s,t;d-q,t;
  4. a-r,s;b-s,t;c-s,t;d-q,r,s,t;

Solution

A As 3α+β2=33α+β=23 ...(i)
And, also α=2+3β ...(ii)
Solving (i) & (ii), we get
23+4β=±23
β=0, -3
So, α=2 and -1
i.e, α=2, 1
(B) Here -3a-2=b+a2 ...(i)
And -6a=b ...(ii)
Solving (i) and (ii),
-3a-2=-6a+a2
a2-3a+2=0
a=1, 2
C Here, 3-3ω+2ω24n+31+ω4n+3+ω24n+3 
3-3ω+2ω24n+31+ω4n+ω8n=0
So, n=1, 2, 4, 5
D q-a=2d
Let q-q=α, d=α2
a=5-α2, b=a+3α2=5+α
Now, aba+b=2
5-α25+α5-α2+5+α=2
α=5, -2
α=5, 2

Asked in: JEE Advanced 2015 (Paper 1)

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