Choose the correct relation between polarisation 'P' and electric susceptibility $^{4} \chi_{e}{ }^{\prime}$…

Choose the correct relation between polarisation 'P' and electric susceptibility $^{4} \chi_{e}{ }^{\prime}$ of dielectric material. $(\mathrm{E}=$ electric field $)$
  1. $\mathrm{P}=\frac{\chi_{\mathrm{e}}}{\mathrm{E}^{2}}$
  2. $\mathrm{P}=\frac{\chi_{\mathrm{e}}}{\mathrm{E}}$
  3. $\mathrm{P}=\chi_{\mathrm{e}} \mathrm{E}$
  4. $\mathrm{P}=\chi_{\mathrm{e}}^{2} \mathrm{E}$

Solution

No Solution.

Asked in: MHT CET 2020 (20 Oct Shift 2)

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