Choose the correct answer. When a point of suspension of pendulum is moved vertically upward with…
Choose the correct answer.
When a point of suspension of pendulum is moved vertically upward with acceleration ' $a$ ', its period of oscillation
decreases
increases
remains same
some times increases and some times decreases
Solution
For a simple pendulum,
$\mathrm{T}=2 \pi \sqrt{\frac{l}{\mathrm{~g}}} \Rightarrow \mathrm{~T} \propto \frac{1}{\mathrm{~g}}$ When the point of suspension is moved vertically upwards with acceleration a, $g$ becomes $g+a$. Hence, $T$ decreases.
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