Chlorobenzene ( X ) when reacted with reagent ' $A$ ' gets converted to phenol (Y). The major product…

Chlorobenzene ( X ) when reacted with reagent ' $A$ ' gets converted to phenol (Y). The major product obtained from nitration of $X$ gets converted to p-nitrophenol $(\mathrm{Z})$ by reaction with reagent B . What are A and B respectively?
  1. $\begin{aligned} & \mathrm{A}=\text { = (i) } \mathrm{NaOH}, 623 \mathrm{~K}, 300 \mathrm{~atm} \text { (ii) } \mathrm{H}^{+} ; \\ & \mathrm{B}=\text { (i) } \mathrm{NaOH}, 443 \mathrm{~K} \text { (ii) } \mathrm{H}^{+}\end{aligned}$
  2. $\begin{aligned} & \mathrm{A}=\text { (i) } \mathrm{NaOH}, 443 \mathrm{~K} \text { (ii) } \mathrm{H}^{+} ; \\ & \mathrm{B}=\mathrm{H}_2 \mathrm{O}, \Delta\end{aligned}$
  3. $\begin{aligned} & \mathrm{A}=\text { (i) } \mathrm{NaOH}, 323 \mathrm{~K} \text { (ii) } \mathrm{H}^{+}: \\ & \mathrm{B}=\text { (i) } \mathrm{NaOH}, 443 \mathrm{~K} \text { (ii) } \mathrm{H}^{+}\end{aligned}$
  4. $\begin{aligned} & \mathrm{A}=\text { (i) } \mathrm{NaOH}, 623 \mathrm{~K}, 300 \mathrm{~atm} \text { (ii) } \mathrm{H}^{+} ; \\ & \mathrm{B}=\mathrm{H}_2 \mathrm{O}, \Delta\end{aligned}$

Solution

Dow's process:

Asked in: AP EAMCET 2024 (18 May Shift 1)

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