Chloro compound of Vanadium has only spin magnetic moment of $1.73 \mathrm{BM}$. This Vanadium chloride has…

Chloro compound of Vanadium has only spin magnetic moment of $1.73 \mathrm{BM}$. This Vanadium
chloride has the formula:
  1. $\mathrm{VCl}_{2}$
  2. $\mathrm{VCl}_{4}$
  3. $\mathrm{VCl}_{3}$
  4. $\mathrm{VCl}_{5}$

Solution

$\mu=\sqrt{n(n+2)}$
$1.73=\sqrt{n(n+2)}$
On calculating the value of $n$ we find $n=1$ No. of unpaired electrons $=1$ hence its configuration will be $\mathrm{V}(23)=[\mathrm{Ar}] 3 d^{3} 4 s^{2}$
$\mathrm{V}^{4+}=[\mathrm{Ar}] 3 d^{1}$
$\therefore$ Its chloride has the formula $\mathrm{VCl}_{4}$ ^

Asked in: JEE-TOPICTESTS-CHEMISTRY

Practice more THE D AND F BLOCK ELEMENTS questions on Aicharya