Chlorine exists as ${ }^{35} \mathrm{Cl}$ (atomic mass $=34.9688 \mathrm{u} ; 75.77 \%$ ) and ${ }^{37}…

Chlorine exists as ${ }^{35} \mathrm{Cl}$ (atomic mass $=34.9688 \mathrm{u} ; 75.77 \%$ ) and ${ }^{37} \mathrm{Cl}$ (atomic mass $=36.9659 \mathrm{u} ; 24.23 \%$ ). The atomic mass of natural existing chlorine is
  1. $35.4527 \mathrm{u}$
  2. $36.4236 \mathrm{u}$
  3. $34.1235 \mathrm{u}$
  4. $32.3458 \mathrm{u}$

Solution

$m_{\mathrm{a}}=(0.7577 \times 34.9688+0.2423 \times 36.9659) \mathrm{u}=35.4527 \mathrm{u}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

Practice more SOME BASIC CONCEPTS OF CHEMISTRY questions on Aicharya